items = ["apple", "banana", "orange"] quantities = [0, 5, 12]
items = ["apple", "banana", "orange"] quantities = [0, 5, 12] inventory = {} for i in range(len(items)): inventory[items[i]] = quantities[i] code avengers answers python 2 new
def format_name(first, last): if len(first) > 3 and len(last) > 3: return f"{last.upper()}, {first.upper()}" else: return "Name too short" The .upper() method ensures case-insensitive matching of expected outputs. The f-string creates the exact comma-space format the auto-grader looks for. Challenge 2: "The Inventory Manager" (Lists & Dictionaries) Problem: You are given a list of item names and a separate list of quantities. Combine them into a single dictionary where the key is the item name and the value is the quantity. Then, write code to print only items with quantity > 0. items = ["apple", "banana", "orange"] quantities = [0,
Forgetting that return stops the function. Combine them into a single dictionary where the
secret = 7 while True: guess = input("Guess a number (or 'quit'): ") if guess == "quit": break guess = int(guess) if guess == secret: print("You win!") break elif guess < secret: print("Too low") else: print("Too high")
The platform now tests if you use dict(zip(items, quantities)) . While that’s more advanced, the accepted answer often prefers the explicit loop because it teaches index tracking. Challenge 3: "The Guessing Game Loop" (While Loops & Break) Problem (New version): Write a guessing game where the secret number is 7. The user has unlimited guesses, but after each wrong guess, print "Too high" or "Too low" . If the user types "quit" , exit the game immediately. If they guess correctly, print "You win!" and stop.
class Student: def __init__(self, name, grades): self.name = name self.grades = grades def average(self): if len(self.grades) == 0: return 0.0 return sum(self.grades) / len(self.grades)